PDA

View Full Version : total newbie ? What to do with a large nitrogen tank?


lawdawg
01-02-2007, 01:59 PM
Hello everyone,

I've been reading of and on here, as my flirtation with a kegerator has grown. I've finally purchased a used True TDD-1, off ebay. It does not come with a tank, or regulator, hoses, etc. Which is okay, since I would have to get a conversion kit for Guinness anyway.

I've called my local supplier of gas, and they do have the 75% / 25% mixture, and the price is not bad either. Only issue is that they only carry it in a 200 cubic feet tank! They are used to supplying bars and such. They will not fill a tank I bring in, because they have their office in another state fill these for them.

So other than having a large tank under the bar (which I can accomodate easily, I'm stuck with the problem of how to get the gas hose into the TDD-1. I've tried to find a manual or spec sheet online that might address this issue, but it seems that most configs for this kegerator use a smaller tank (which will fit in the fridge.)

Can anyone offer some advice on how to do this? I'd rather not have to go cutting holes in the TDD-1, etc. Is it possible that they will already have an outlet/inlet hole for just this configuration?

Thanks for helping me out,
Adam

zoom6zoom
01-02-2007, 04:40 PM
Most home bars use strictly CO2, not a nitrogen mix. Some use that for stouts, but it requires different regulators than straight CO2.

You don't say where you're located - other members in your area would surely have suggestions for you.

lawdawg
01-02-2007, 04:42 PM
sorry, I'm in Springfield, MO.

I'm looking to dedicate this kegerator to Guinness exclusively, or at least until I move onto another Stout! ;)

Thanks for the reply,
Adam

HogieWan
01-02-2007, 04:51 PM
Originally posted by lawdawg
sorry, I'm in Springfield, MO.

I'm looking to dedicate this kegerator to Guinness exclusively, or at least until I move onto another Stout! ;)

Thanks for the reply,
Adam

you can push guinness with straight co2 (for the better imo).